Question

find the value of a, if x-2 is a factor of the polynomial p(x)= x³ +2x²-x+a​

Answer 1

Step-by-step explanation:

p(x)= x³ +2x²-x+a

p(2)= 2³ +2×2²-2+a

= 8+8-2+a

= 14+a

a=-14

Answer 2

Answer:

The polynomial x3 +2x 2

−x−2=0 can be factorized as follows:

x3 +2x 2 −x−2=0

⟹x 2 (x+2)−1(x+2)=0

⟹(x 2 −1)(x+2)=0

⟹ x 2−1=0 or x+2=0

⟹ x2 =1 or x=−2

x=1, x=−1 and x=−2

Hence, the zeroes of the polynomial x

3 +2x 2−x−2=0 are 1,−1,−2.

Step-by-step explanation:

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