Question

find the value of a if x^3-ax^2+6-a is divisible by x-a
plz don't tell wrong answer urgent​

Answer 1

Answer:

its 6 and thats it !!!!!!!!!!!

Answer 2

$let \: the \: dividend \: be \: g(x) \: and \: the \: factor \: be \: p(x)$

$dividend \: = {x}^{3} - a {x}^{2} + 6 - a$

$factor = x - a$

$x - a = 0 \\ p(x) = a$

$according \: to \:factor \: theorum$

$g(x) = {x}^{3} - a {x}^{2} + 6 - a \\ g(a) = {a}^{3} - a \times {a}^{2} + 6 - a \\ {a}^{3} - {a}^{3} + 6 - a = 0 \\ 6 - a = 0 \\ a = - 6$

hope it helps u❤