Find the value of a if x^3+ax+2a-2 is exactly divisible by x+1
Answers
Answered by
2
Answer:
3
Step-by-step explanation:
3 is the correct answer
Answered by
2
Answer:
x + 1 = 0
x = -1
p(x) = x^3 + ax^2 + 2a - 2
p(-1) = (-1)^3 + a(-1)^2 + 2a - 2
= -1 + a + 2a - 2 = 0
= 3a - 3 = 0
= 3a = 3
= a = 3/3 = 1
Similar questions