Question

find the value of a if (x-5) is a factor of (x³-3x²+ax-10)​

Answer 1

since (x-5) is a factor of (x3-3x2+ax-10)

x-5=0

x=5

now

P(x)=0

P(5)=0

(5)3-3*(5)2+a*5-10=0

125-75+5a-10=0

40+5a=0

5a=-40

a=-40/5

a=-8

since a=-8

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Answer 2

Hope this helps you........