Question

find the value of a if (x-a) is a factor of a6-a(x5)+x4-ax3+3x-a+2

Answer 1

It's pretty easy and simple.

Let g(x) be factor and f(x) be polynomial.

g(x) must be assumed as 0. So that we can find value of x.

g(x) = x - a = 0
x = a .......... 1

f(a) = 6a - a(5a) + 4a - 3a^2 + 3a - a + 2



$12a \: + \: 5 {a}^{2} - \: 3 {a}^{2} \: + \: 2 \\ 12a \: + \: 2 {a}^{2} \: + \: 2 \: = \: 0 \\ 12 \: + \: 2 {a}^{2} \: + \: 2 \: = \: 0 \\ 2 {a}^{2} \: = \: - 2 - 12 \: = \: - 14 \\ {a}^{2} = - 14 \div 2 \: = \: - 7 \\ a \: = \: \sqrt{ - 7} = - 2.645752$
May b wrong. Just trying

Answer 2

Answer:

Step-by-step explanation:

It's pretty easy and simple.

Let g(x) be factor and f(x) be polynomial.

g(x) must be assumed as 0. So that we can find value of x.

g(x) = x - a = 0

x = a .......... 1

f(a) = 6a - a(5a) + 4a - 3a^2 + 3a - a + 2

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