find the value of a if (x-a) is a factor of polynomial x^6-ax5+x^4-ax^3+3x-a+2
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Answered by
6
Solution:
Let p(x) = x^6-ax^5+x⁴-ax³+3x-a+2
If (x-a) is a
factor of p(x) then p(a) = 0
/* By factor theorem */
a^6-a(a^5)+a⁴-a(a³)+3a-a+2=0
=> a^6-a^6+a⁴-a⁴+3a-a+2=0
=> 3a-a+2 = 0
=> 2a+2 = 0
=> 2a = -2
=> a = (-2)/2
=> a = -1
Therefore,
a = -1
••••
Answered by
0
Answer:
Let p(x) = x^6-ax^5+x⁴-ax³+3x-a+2
If (x-a) is a
factor of p(x) then p(a) = 0
/* By factor theorem */
a^6-a(a^5)+a⁴-a(a³)+3a-a+2=0
=> a^6-a^6+a⁴-a⁴+3a-a+2=0
=> 3a-a+2 = 0
=> 2a+2 = 0
=> 2a = -2
=> a = (-2)/2
=> a = -1
Step-by-step explanation:
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