Question

Find the value of a, if (x – a) is a factor of x-ax+x+2.
​

Answer 1

Let functions f(x) and g(x) be polynomials such that g(x) is factor of f(x).

Then the root of g(x) will be also the root of f(x).

So, as per the question (x−a) is a factor of x

6

−ax

5

+x

4

−ax

3

+3x−a+2=0

Root of x−a is a.

Therefore a is also the root of x

6

−ax

5

+x

4

−ax

3

+3x−a+2=0.

putting x=a

⇒a

6

−aa

5

+a

4

−aa

3

+3a−a+2=0

⇒a

6

−a

6

+a

4

−a

4

+2a+2=0

⇒2a+2=0

⇒a=−1

So, the value of a is −1.

Answer 2

Answer:

Since x - a is a factor of p(x) = x3 − ax2 + x + 2.

→ x = a and p(a) = 0

→ p(a) = a3 − a3 + a + 2 = 0

→ a = -2

Step-by-step explanation:

MARK ME BRAINLIST