find the value of a if x-a is a factor of x3-ax2+2x+a-1
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Answered by
22
Heya !!!!
Given that ,
( X -A) is a factor of the given polynomial.
( X - A) = 0
X = A
P(X) = X³ - AX² + 2X + A - 1
P(A) = (A)³ + A × (A)² + 2 × A + A - 1
=> A³ - A³ + 2A + A - 1 = 0
=> 3A = 1
=> A = 1/3
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
Given that ,
( X -A) is a factor of the given polynomial.
( X - A) = 0
X = A
P(X) = X³ - AX² + 2X + A - 1
P(A) = (A)³ + A × (A)² + 2 × A + A - 1
=> A³ - A³ + 2A + A - 1 = 0
=> 3A = 1
=> A = 1/3
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
Answered by
13
Given that (x - a) is the factor,
So, x - a = 0
x = a
Putting the value of x in given equation :
x³ - ax² + 2x + a - 1 = 0
(a)³ - a(a)² + 2(a) + a - 1 = 0
a³ - a³ + 2a + a - 1 = 0
3a - 1 = 0
3a = 1
I hope this will help you
(-:
So, x - a = 0
x = a
Putting the value of x in given equation :
x³ - ax² + 2x + a - 1 = 0
(a)³ - a(a)² + 2(a) + a - 1 = 0
a³ - a³ + 2a + a - 1 = 0
3a - 1 = 0
3a = 1
I hope this will help you
(-:
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