Find the value of a if (x-a)is a factor of x4-a2+x+3x-a
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Answered by
2
Step-by-step explanation:
Let f(x) = x4-a2x2+3x-a
(x+a) is a factor of f (x)
f (-a) = 0
(-a)4-a2(-a)2+3(-a)-a = 0
a4-a4-3a-a = 0
-4a = 0
a = 0
Answered by
0
You can find the value using remainder theorem.
REMAINDER THEOREM: When (x-a) is a factor of x^4-a^2+4x-a, then, if you substitute x with +a... it will result in a zero....
a^4-a^2+4a-a=0
a^3-a+3=0
Now use cubic equations formula to get a value.
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