find the value of 'a' if (x_a) is a factor of x5_a2x3+ 2x+ a+ 3, hence factorie x2 _ 2ax_ 3
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f(x) = x⁵- a²x³ + 2x + a + 3
x-a is a factor of f(x).
That implies, f(a) = 0
f(a) = a⁵ - a².a³ + 2a + a + 3 = 0 ⇒ a = -1
So , f(x) = x⁵ - x³ +2x + 2
Factorise : x² - 2ax - 3 = x² + 2x - 3 = x² + 3x - x + 3 = (x-3)(x+1)
x-a is a factor of f(x).
That implies, f(a) = 0
f(a) = a⁵ - a².a³ + 2a + a + 3 = 0 ⇒ a = -1
So , f(x) = x⁵ - x³ +2x + 2
Factorise : x² - 2ax - 3 = x² + 2x - 3 = x² + 3x - x + 3 = (x-3)(x+1)
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