Question

find the value of A in following:1 A×A=A 9 ​

Answer 1

Answer:

hajjajakakanabsskkabsbxjsknsnnakaa

Answer 2

Given: A(a,3),B(2,1) and C(5,a) are collinear.

∴ Slope of AB= Slope of BC

⇒2−a1−3=5−2a−1

⇒2−a−2=3a−1

⇒−6=(2−a)(a−1)

⇒−6=2a−2−a2+a

⇒a2−3a−4=0

⇒a2−4a+a−4=0

⇒(a−4)(a+1)=0

a=4,−1

For a=4

Slope of BC=5−2a−1=34−1=33=1

Equation of BC;(y−1)=1(x−2)

⇒y−1=x−2

⇒x−y=1

For a=−1

Slope of BC=5−2a−1=3−1−1=−32

Equation of BC:(y−1)=−32(x−2)⇒3y−3=4−2x

⇒2x+3y=7