Question

. Find the value of a in polynomial x²+ax-20 if 4 is one of its zero .बहुपद x²+ax-20 में a का मान ज्ञात करें यदि 4 बहुपद का शून्य है। *
2 points
1​

Answer 1

Answer:

Your answer is 1

Step-by-step explanation:

Let f(x) = x^2 + ax - 20

Also let g(x) = 4

Now if g(x) is factor of f(x) then substitute the value of g(x) in f(x)

>> f(x) = x^2 + ax - 20 = 0

>> putting x = 4

>> f(4) = 4^2 +4a - 20 = 0

>> = 16 + 4a - 20 = 0

>> =4a = 20 - 16

>>. = a = 1

>>