Question

Find the value of a in the following:

Answer 1

here sthe answer of your question

Answer 2

a = 2

Step-by-step explanation:

$\frac{6}{3 \sqrt{2} - 2 \sqrt{3} } = 3 \sqrt{2} - a \sqrt{3}$

$\frac{6}{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } = 3 \sqrt{2} - a \sqrt{3}$

$\frac{6(3 \sqrt{2} + 2 \sqrt{3} )}{( {3 \sqrt{2} )}^{2} - ( {2 \sqrt{3)} }^{2} } = 3 \sqrt{2} - a \sqrt{3}$

$\frac{18 \sqrt{2} - 12 \sqrt{3} }{9 \times 2 - 4 \times 3} = 3 \sqrt{2} - a \sqrt{3}$

$\frac{18 \sqrt{2} - 12 \sqrt{3} }{18 - 12} = 3 \sqrt{2} - a \sqrt{3}$

$\frac{6(3 \sqrt{2} + 2 \sqrt{3)} }{6} = 3 \sqrt{2} - a \sqrt{3}$

3√2 + 2√3 = 3√2 - a√3

a√3 = 2√3

a = 2