Question

find the value of a in the following
6 by 3 root 2 - 2 root 3 =3 root 2 - a root 3​

Answer 1

Step-by-step explanation:

6/3√2 -2√3=3√2-a√3

2/√2-2√3-3√2=-a√3

rationalize 1st term

2√2/√2*√2=2√2/2=√2

√2-3√2-2√3=-a√3

-2√2-2√3=-a√3

-(2√2/√3+2√3/√3)=-a

a=2√2/√3+2