Question

find
-the
value of a is
x if 4/3,x,4/27 are in G.P​

Answer 1

Answer:

The value of x is ±4/9

Step-by-step explanation:

Here  $4/3, x , 4/27$ are in G.P. series

Now,

   $x^{2} = (4/3)*(4/27)$

⇒$x^{2} =16/81$

⇒x = ±4/9