find the value of a it 3x+ay=9 is passing through the point (-5,1)
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Given that,
4x+3y=1 ⟶(1)
3x−y+9=0⟶(2)
Solving the equations simultaneously, we get
4x+3y=1×1
3(3x−y)=−9×3
4x+3y=1
9x−3y=−27
13x=−26
x=−2
y=−3
B(−2,−3)
∴ Slope of the passing through the point (0,−2) and (−2,−3)
⇒m=
−2−0
−3+2
=
−2
−1
⇒m=
2
1
So, the equation of line is given as,
y−y
1
=m(x−x
1
)
⇒ (y+2)=
2
1
(x−0)
⇒ 2y+4=x
⇒ x−2y+4=0
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