find the value of a line 5y=ax+10,will pass through (1,3)
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Answered by
2
Answer:
5
Step-by-step explanation:
Let us assume that 5y= ax+ 10 passes through (1,3)
Then 5(3)= a(1)+10
15= a+10
a=5
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Answered by
0
Answer:
The given straight line is
5y = ax + 10 ...(i)
When the line (i) will pass through the point (2, 3),
5 (3) = a (2) + 10
➩ 15 = 2a + 10
➩ 2a = 15 - 10
➩ 2a = 5
➩ a =
Now, putting a = in (i), we get the required straight line as
5y = x + 10
➩ 10y = 5x + 20
Again when the line (i) passes through the point (1, 1),
5 (1) = a (1) + 10
➩ 5 = a + 10
➩ a = 5 - 10
Now, putting a = - 5 in (i), we get the required line as
5y = (- 5)x + 10
➩ y = - x + 2
Step-by-step explanation:
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