Question

Find the value of a?
please answer only if you know

Answer 1

hi ,

here is your answer!!!

given ,

=> a² -10 a = 5

or


=> a² -10a -5 =0


=> on applying quadratic formula


- b ±√ D
---------------
2a


D = b² - 4ac

given ,

a = 1


b = - 10


c = - 5


therefore ,

D = b² - 4ac


=> (-10)² - 4 x 1 -5

=> 100 +20

=> 120


on putting the value in formula

we get


=> - b ±√D / 2a


=> -(-10) ± √120 /2 x1


10 ± √120 / 2



hence ,


your answer is =>


10 - √120 / 2

and


10 + √120 /2




hope it helps you dear!!!!
$thanks$

☺☺☺

Answer 2

a²-10a = 5

a²-10-5 = 0

it's form of ax²+bx+c = 0

so a = 1 b = -10 c = -5

according to Shridhar's law

(+- means plus or minus)

a = -b +-√b²-4ac/2a

a = -(-10)+-√(-10)²-4(1)(-5)/2(1)

a = 10+-√100+20/2

a = 10+-√120/2

a = 10+-√4×30/2

a = 10+-2√30/2

( take common as 2)

a = 2(5+-√30)/2

a = 5+-√30

a = 5+√30. OR. a = 5-√30

so the value of a is 5+√30 or 5 -√30

fill the value of a to check answer is right