Question

Find the value of a point (2,2) is present on the graph of equation 4x+ay=14

Answer 1

Solution:

To Determine: The value of 'a'.

Given Equation:

→ 4x + ay = 14

Since, the point (2, 2) lies on the line 4x + ay = 14, it must be a solution of the equation.

→ 4 × 2 + a × 2 = 14

→ 8 + 2a = 14

→ 2a = 6

→ a = 3

Hence: a = 3

So, the equation is -

→ 4x + 3y = 14 (Answer)

Learn More:

1. Slope Intercept form.

$\rm\longrightarrow y=mx+c$

2. Point slope form.

$\rm\longrightarrow y-y_{1}=m(x-x_{1})$

3. Two point form.

$\rm\longrightarrow y-y_{1}=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1})$

Answer 2

putting x = 2 , y = 2 in 4x + ay = 14 .

⇒ 4(2) + 2(a) = 14

⇒ 2a = 6

⇒ a = 3