Math, asked by Harshita8053, 1 month ago

find the value of a

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Answered by suraj5070
294

 \sf \bf \huge {\boxed {\mathbb {QUESTION}}}

 \tt Find \:the \:value \:of \:a

 \sf \bf \huge {\boxed {\mathbb {ANSWER}}}

 \sf \bf {\boxed {\mathbb {GIVEN}}}

  •  \sf \bf \angle BGH=2a
  •  \sf \bf \angle DHG=3a

 \sf \bf {\boxed {\mathbb {TO\:FIND}}}

  •  \sf \bf Value \:of \:a

 \sf \bf {\boxed {\mathbb {SOLUTION}}}

 {\pink {\underline {\bf {\pmb {Value \:of \:a}}}}}

 \bf \angle BGH+\angle DHG ={180}^{\circ}\longrightarrow \Big(Consecutive\:interior\:angles\Big)

 {\underbrace {\overbrace {\orange {\pmb {Substitute \:the\:values}}}}}

 \bf \implies 2a+3a={180}^{\circ}

 \bf \implies 5a={180}^{\circ}

 \bf \implies a=\dfrac{180}{5}

 \implies {\blue {\boxed {\boxed {\purple {\mathfrak {a={36}^{\circ}}}}}}}

 {\underbrace {\red {\underline {\red {\overline {\red {\sf {\pmb {{\therefore}The\:value \:of \:a\:is\:{36}^{\circ}}}}}}}}}}

 \sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}

__________________________________________

 \sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}

 {\green {\sf Types \:of \:pairs\:of \:angles}}

 \sf Complementary\:angles

 \sf Supplementary\: angles

 \sf Alternate Interior \:Angles

 \sf Consecutive \:Interior\: Angles

 \sf Adjacent \:angles

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