Question

Find the value of ‘a’ so that (-2) is a root of 2

2 – + = 0​

Answer 1

Step-by-step explanation:

Given equation x²+bx+12=0

one root is 2

so put x=2

4+2b+12=0

2b=−16

b=−8

Now roots of equation x² +bx+q=0 are equal

So, D=0

b²−4q=0

(−8)²−4q=0

4q=64⇒q=16