Question

Find the value of 'a' so that (2x-1) will be a factor of 2x^3+ ax^2+ 11x + a + 3. ?​

Answer 1

Answer:

2(1/2)³+a(1/2)²+11(1/2)+1/2+3

2(1/8)+a(1/4)+11/2+1/2+3

1/4+a/4+11/2+1/2+3

taking 4 LCM..

1+a+22+2+12

a=37

Answer 2

Answer:

2x-1=0

=x=1/2.

f(x)=2x^3+ax^2+11x+a+3

f(1/2)=0

=2×(1/2)^3+a(1/2)^2+11×(1/2)+a=0

=(1/4)+a/4+11/2+a=0

=a+a/4= -[11/2+1/4]

=5a/4 = 23/4

=a = 23/4×4/5

=a = 23/5.