Question

find the value of (a) so that p(x)=x³-ax²-13x+15 is exactly divisible by x-1​

Answer 1

Answer:

since x-1=0

therefore x=1

substituting the value of x=1 in p(x) we get,

1-a-13+15

and since x-1 is a factor of p(x)

therefore 1-a-13+15=0

=3-a=0

this implies a=3

therefore value of a =3 so that p(x) is exactly divisible by x-1

Answer 2

Answer:

Hey ur answer

Step-by-step explanation:

Value of a=3 so that p(x) is exactly divisible by x-1

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