Question

find the value of (a) so that p(x)=x³-ax²-13x+15 is exactly divisible by x-1​

Answer 1

Answer:5

Step-by-step explanation:

if p(x) has to be exactly divisible by x-1 then P(1)=0

p(1) = 1^3-a(1)^2-13(1)+15=0

3-a-13+15=0

a=5