Find the value of 'a' so that the point (3.9) lies on the line represented by 2x
3y=5.
(a)1/3 (b)1/6 (c)1/12 (d)2
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Since (3,a) lie on the line 2x - 3y = 5 ...(1)
Since (3,a) lie on the line 2x - 3y = 5 ...(1)Substituting x=3 and y=a in (1) we get
Since (3,a) lie on the line 2x - 3y = 5 ...(1)Substituting x=3 and y=a in (1) we get 2(3) - 3(a) = 5
Since (3,a) lie on the line 2x - 3y = 5 ...(1)Substituting x=3 and y=a in (1) we get 2(3) - 3(a) = 5 6 - 3a = 5
Since (3,a) lie on the line 2x - 3y = 5 ...(1)Substituting x=3 and y=a in (1) we get 2(3) - 3(a) = 5 6 - 3a = 5⇒3a=1
Since (3,a) lie on the line 2x - 3y = 5 ...(1)Substituting x=3 and y=a in (1) we get 2(3) - 3(a) = 5 6 - 3a = 5⇒3a=1⇒a=1/3.
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Answer:
your question answer is b
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