Question

Find the value of a, so that the point 3,a lie on the line 2x-3y =5

Answer 1

Hi ,

i ) It is given that ,

( 3 , a ) lies on the line 2x - 3y - 5 = 0

Substitute x = 3 , y = a in the equation

We get ,

2 × 3 - 3a - 5 = 0

6 - 3a - 5 = 0

1 - 3a = 0

1 = 3a

1/3 = a

a = 1/3

ii ) If the line cuts the x - axis ,

to find the coordinates , put y = 0

in the equation , we get

2x - 3 × 0 - 5 = 0

2x - 5 = 0

2x = 5

x = 5/2

Therefore ,

Required point = ( 5/2 , 0 )

I hope this helps you.

: )

Answer 2

(3,a) lies on 2x-3y=5
2(3)-3a=5
6-3a=5
3a=6-5
3a=1
a=1/3