Find the value of a , so that the point
(3, a) lies on the line represented by
2x-3yz.
Answers
Answered by
1
Answer:
sticd Genius
Hi ,
i ) It is given that ,
( 3 , a ) lies on the line 2x - 3y - 5 = 0
Substitute x = 3 , y = a in the equation
We get ,
2 × 3 - 3a - 5 = 0
6 - 3a - 5 = 0
1 - 3a = 0
1 = 3a
1/3 = a
a = 1/3
ii ) If the line cuts the x - axis ,
to find the coordinates , put y = 0
in the equation , we get
2x - 3 × 0 - 5 = 0
2x - 5 = 0
2x = 5
x = 5/2
Therefore ,
Required point = ( 5/2 , 0 )
I hope this helps you.
: )
Answered by
1
Answer:
Step-by-step explanation:
It is given that ,
( 3 , a ) lies on the line 2x - 3y - 5 = 0
Substitute x = 3 , y = a in the equation
We get ,
2 × 3 - 3a - 5 = 0
6 - 3a - 5 = 0
1 - 3a = 0
1 = 3a
1/3 = a
=>a=1/3
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