Question

Find the value of 'a 'so that the point (3,a) lies on the line represented by 2x-3y=5.

Answer 1

put (3,a) in line 2x-3y =5

2(3)-3(a) =5

3a =1
a=1/3

Answer 2

Answer:

Thus, the value of 'a' is $\frac{1}{3}$.

Step-by-step explanation:

We are given the equation of the line is, $2x-3y=5$

It is required to find the value of 'a' such that the point (3,a) lies on the line.

So, for the point to lie on the line, the point must satisfy the equation.

So, we will substituting the values, x= 3 and y= a,

$2x-3y=5$

implies $2\times 3-3\times a=5$

i.e. $6-3a=5$

i.e. $3a=6-5$

i.e. $3a=1$

i.e. $a=\frac{1}{3}$

Thus, the value of 'a' is $\frac{1}{3}$.