find the value of a so that the points 3x lies on the line presented by 2x-3y+5=0
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(3,a) lies on the line 2x-3y-5=0 it means (3,a) is a solution of this line
so 2x-3y-5=0
2x-3y=5
2*3-3a=5
6-5=3a
1/3=a
now coordinates of the point where line cut x axis
on x axis every point is of the form(x,0)
so 2x-3y=5
2x-3*0=5
2x=5
x=5/2
so 2x-3y-5=0
2x-3y=5
2*3-3a=5
6-5=3a
1/3=a
now coordinates of the point where line cut x axis
on x axis every point is of the form(x,0)
so 2x-3y=5
2x-3*0=5
2x=5
x=5/2
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