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find the value of 'a' such that PQ=QR where P,Qand R are the points whose coordinate are (6,1) (1,3) and (a,b) respectively​

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Answered by sk9815729
1

Step-by-step explanation:

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Answered by Kritika25675
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Step-by-step explanation:

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>>Applied Mathematics

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Find the value of x such that PQ=QR where the coordinates of P,Q and R are (6,−1),(1,3) and (x,8) respectively.

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Coordinate of point P,Q and R are P(6,-1),Q(1,3) and R(x,8)

Given, PQ=QR

So by distance formula we have,

Distance between two points =

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

PQ=

(6−1)

2

+(−1−3)

2

=

25+14

=

41

∴PQ

2

=41=QR

2

but, QR

2

=(x−1)

2

+25

41=x

2

+1−2x+25

⇒41=x

2

+1−2x+25

⇒x

2

−2x+26=41

⇒x

2

−2x−15=0

⇒x

2

−5x+3x−15=0

⇒x(x−5)+3(x−5)=0

⇒(x+3)(x−5)=0

⇒x=−3,5

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