Question

Find the value of a such that quadratic equation (a-3)x2+ 2(a-4)x + 4 = 0 has equal roots​

Answer 1

Answer:

Step-by-step explanation:

If discriminant(D) = 0 then equation has real and equal roots

D=b^2-4ac=0

[2(a-3)]^2-4(a-4)(4)=0

4a^2+36-24a-16a+64=0

4a^2-40a+100=0

a^2-10a+25=0

[a=5] is the answer