Question

find the value of a such that the
following
equations have
unique solution

ax + 2y - 2z - 1 = 0, 4x + 2ay - z - 2 = 0
6x + 6y + az - 3 = 0.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

for unique solution ;

∆ ≠ 0

∆ = a(2a²+6) -2(4a+6)-2(24-12a)

∆= 2a³+22a-60 or, 2(a³+11a-30)

∆≠0

=> 2(a³+11a-30)≠0

since there exists no 'a' for which ∆=0

hence , the system of equations have unique solution for all x € R .