find the value of a such that the number 1245a is a multiple of 9 .
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Answer:
Step-by-step explanation:
1245a is a no. divisible by 9
hence
if the sum of the digits of the no. is divisible by 9 then that no. is also divisible by 9
1245a
sum of digits= 1+2+4+5+a=12+a
the nearest no. to 12 which is divisible by 9 is 18 so
12+a should be 18
a=6
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the value of a is 6.
Sum of the given digits =12
But 12 is not divisible by 9 therefore to make it a multiple of 9. simply add 6 to it =12+6=18
and 18 is divisible by 9
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