Question

find the value of a such that (x-4) is a factor of 5x^3-7x^2-ax-28​

Answer 1

Answer:

$\{a=45}$

Step-by-step explanation:

if (x-4) is a factor of the polynomial

$\underline{5x^3-7x^2-ax-28}$

then the given polynomial is equal to 0

if we solve x-4

we get

$\boxed{x=4}$

now putting this value in the given polynomial

$5(4) {}^{3} - 7 (4) {}^{2} - a(4) - 28 = 0$

$320 - 112 - 4a - 28 = 0$

$180 - 4a = 0$

$- 4a = - 180$

$a = \frac{ - 180}{ - 4}$

$a = 45$

Answer 2

Answer:

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