Question

Find the value of a such that (x+a) is a factor of the polynomial p(x) = x4 - a2x2 + 2x+a+3​

Answer 1

Answer:

0

Step-by-step explanation:

P(-a) = (-a)^4 - a^2(-a)^2 + 3(-a) - a

0 = a^4 - a^(2+2) - 3a - a

0 = a^4 - a^4 - 3a - a  

0 = -4a  

0/-4 = -4a/-4

0 = a (ANSWER)

Answer 2

Answer:

p (x) = x^4 - a^2x^2 + 2x+a+3

Since ( x+a ) is a factor of the polynomial then, f ( -a ) = 0

i.e. f ( -a ) = (-a)^4 -a^2*(-a) ^2 ​ + 2(-a) + a+ 3

or, 0 = a^4 -a^4 -2a +a+3

or, 0 = -a +3

----> a =3

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