find the value of a when ay^ - 9y + 4a is divided by 2y - 1 gives the remainder 5/6.
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given, g(x) = 2y - 1 =0
y = 1 / 2
according to question,
ay^2 - 9y + 4a = 5 / 6
a( 1 / 2)^2 - 9( 1/ 2) + 4 a = 5/ 6
(a / 4 + 4a ) = ( 5 /6 + 9 / 2 )
17a / 4 = (10 + 54) / 12
17 a / 4 = 64 / 12
a =4× 64 / 17 × 12
a = 64 / 51
◆●◆hope it helps ●◆●
y = 1 / 2
according to question,
ay^2 - 9y + 4a = 5 / 6
a( 1 / 2)^2 - 9( 1/ 2) + 4 a = 5/ 6
(a / 4 + 4a ) = ( 5 /6 + 9 / 2 )
17a / 4 = (10 + 54) / 12
17 a / 4 = 64 / 12
a =4× 64 / 17 × 12
a = 64 / 51
◆●◆hope it helps ●◆●
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