Question

Find the value of A when B = 8;
if A^2 + B^2 + 20 = (A - B + 14)^2​

Answer 1

Answer:

here

given

x=?

y=8

${x}^{2} + {y}^{2} + 20 = (x - y + 14) {}^{2} \\ = > {x}^{2} + 64 + 20 =( x - 8 + 14) {}^{2} \\ = > {x}^{2} + 84 = {x}^{2} + 12x + 36 \\ = > 12x = 84 - 36 \\ = > 12x = 48 \\ = > x = 4$

here a=X

b=y

hence X=4

y=8

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