Question

Find the value of 'a', when the distance between the points (3. a) and (4, 1) is √10
units.​

Answer 1

Answer:

$a = 4 \: \: \: \: \: or \: \: \: \: a = - 2$

Step-by-step explanation:

$(3 \: \: \: \: a) \: \: \: \: \: \: \: \: (4 \: \: \: \: 1) \\ \\ \sqrt{( {(4 - 3)}^{2} + {(a - 1)}^{2} )} = \sqrt{10} \\ 1 + {(a - 1)}^{2} = 10 \\ {(a - 1)}^{2} = 9 \\ (a - 1) = 3 \: \: \: \: \: \: \: \: \: \: (a - 1) = - 3 \\ a = 4 \: \: \: \: \: or \: \: \: \: a = - 2$