Find the value of a when the distance between the points (3,a) and (4,1) is v10.
Answers
Answered by
0
Answer:
NO
Step-by-step explanation:
Answered by
0
Answer:
Let A(3,a) and B(4,1) be the points of a line AB
Distance AB=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
⇒
10
=
(1−a)
2
+(4−3)
2
Squaring both sides, we get
⇒10=(1−a)
2
+(4−3)
2
⇒10=1+a
2
−2a+1=0
⇒a
2
−2a−8=0
⇒a
2
−4a+2a−8=0
⇒a(a−4)+2(a−4)=0
⇒(a−4)(a+2)=0
∴a=−2 or a=4
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