Question

find the value of a when the lines 2x+3y=4 and4x+(a+1)y+6=0, are parallel ​

Answer 1

Answer:

a=5

Step-by-step explanation:

$lines \: are \: parallel \\ \frac{2}{4} = \frac{3}{a + 1} \\2(a + 1) = 12 \\ a + 1 = 6 \\ a = 6 - 1 \\ a = 5$