Question

find the value of a when x^6-ax^5+x^4-ax^3+3x-a+5 (if x=a)​

Answer 1

Answer:

brilliant question bro

Answer 2

Answer:

value of a= -1

Step-by-step explanation:

given x= a

put x = a in p(x)

p(a)= a^6-a×a^5+a^4-a×a^3+3a-a+2

= 2a+ 2

here ( x-a) is the factor .

so, remainder must be 0

so p(a)= 0

2a +2= 0

2a= -2

a= -1

thank you!!