Question

Find the value of a ; where (x-a) is a factor of x3-ax2+6x-a.

Answer 1

Step-by-step explanation:

Here, p(x)=x

3

+ax

2

+6x−a, and the zero of x−a is a

So, p(a)=a

3

+a×a

2

+6×a−a

=2a

3

+5a

So, by the Remainder Theorem, 2a

3

+5a is the remainder when x

3

+ax

2

+6x−a is divided by x−a.

Answer 2

Step-by-step explanation:

Hope it helps you buddy!!

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