Find the value of a which point p(a/3,12) is the mid point of the line segment joining the poit q(-5,4) and (-1,0)
Answers
Answered by
0
For mid point,
x = ( x1 + x2 ) / 2
Y =( y1 + y2 ) / 2
a / 3 = ( - 5 - 1 ) /2
12 = ( 4 + 0 ) /2
a = - 3 × 3 = - 9
So, a = - 9.
x = ( x1 + x2 ) / 2
Y =( y1 + y2 ) / 2
a / 3 = ( - 5 - 1 ) /2
12 = ( 4 + 0 ) /2
a = - 3 × 3 = - 9
So, a = - 9.
Similar questions