Question

find the value of a (x-a) is a factor of x^2-ax+2x+a-1​

Answer 1

Answer:

Step-by-step explanation:

By factor theorem,

P(a)=0

=> a^2 -a.a +2a +a-1 =0

=> a^2 - a^2 +2a+a-1 =0

=> 3a-1 =0

=>3a=1

=>a =1/3

Therefore a=1/3

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Answer 2

Answer:

As We know that :-

Remainder therom.

when p(x) is divided by (x-1) , so the remainder is p(1).

Step-by-step explanation:

Given:-

p(x)=x^2-ax+2x+a-1 is divided by a(x-a)

Remainder = a(x-a)

= ax - a^2

= ax= a^2

= x = a^2/a

= x = a

So ,,

Remainder = p(x) = p(-a)

p(-a)= (-a)^2 - a(-a)+ 2(-a)+a-1

= a+a^2 -2 a+a-1

= 2a -2 a + a^2 -1

= a^2-1

p(-a) = a^2 -1.

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