Question

Find the value of : a^ x-y . a^ y-x​

Answer 1

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${a}^{x} - \: y \times {a}^{y - x} \\ = {a}^{x} - y \: \times {a}^{y} - {a}^{x} \\ = - y \times {a}^{y} \\ = - {a}^{y} y$

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Answer 2

Answer is 0

Process- a^x-y × a^y-x

= a^ x-y+y-x. ( a^b × a^c = a^a+b )

= a^0= 1 {for any value of a, a^0=1 }