Question

find the value of a° in the following equation:

6÷3√2-2√3=3√2-a√3​

Answer 1

Answer:

$\mathcal{ Solution}$

$\mathfrak\red{ \frac{6}{3 \sqrt{2} - 2 \sqrt{3} } = 3\sqrt{2} - a\sqrt{3} }$

$\mathcal { Rationalise \: the \: Denominator}$

$\mathfrak\red{ \frac{6}{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } = 3 \sqrt{2} - a \sqrt{3} }$

$\mathfrak\red{ \frac{6(2 \sqrt{3} + 2 \sqrt{3} ) }{ {(3 \sqrt{2}) }^{2} - { (2\sqrt{3}) }^{2} } }$

$\mathfrak\red{ \frac{6(3 \sqrt{2} + 2 \sqrt{3}) }{18 - 12} }$

$\mathfrak\red{ 3\sqrt{2} + 2 \sqrt{3} }$

From here the value of a is 2

Step-by-step explanation:

Hope this helps you.

# By Sparkly Princess