find the value of a²+ 4b²+9c²+4ab- 12bc- 6ca, when a=3,b=2,and c=-1
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answer is 0 it's my answer
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(3)²+4(2)²+9(-1)²+4×3×2-12×2(-1)-6×(-1)×3
9+16+9+24+24+18
18+16+48+18
36+64
100
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