Question

Find the value of a2+b2+c2-2ab-2ac+2bc when a=17 b=15 and c =13

Answer 1

${a}^{2} + {b}^{2} + {c}^{2} - 2ab - 2ac + 2bc = {(a - b - c)}^{2} \\ or$
${(17 - 15 - 13)}^{2} = {(17 - 28)}^{2}$
${( - 11) }^{2} = 121$
therefore the value will be 121