Find the value of a² + b² + c² - 2ab - 2bc - 2ca + 3abc.
a = 2
b = 3
c = 1
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Answer:
Hence the right answer is 10
Step-by-step explanation:
(2)^2+(3)^2+(1)^2-(2*2*3)-(2*3*1)-(2*1*2)+(3*2*3*1)
4+9+1-12-6-4+18
10
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