find the value of a2+b2+c2-ab-bc-ca when a-b=2 and b-c=3 and c-a=4
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Answer:
-8
Step-by-step explanation:
a*2+b*2-ab-bc-ca+c*2
(a-b)*2+ab-bc-ca+c*2
4-b(c-a)+c(c-a)
4-(c-a)(b-c)
4-(4)(3)
4-12
-8
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